1.

What will be the value of k, if one zero of x^2+(k-3)x-16=0 is additive inverse of other?(a) 4(b) -4(c) -3(d) 3This question was addressed to me in unit test.The above asked question is from Zeros and Coefficients of Polynomial topic in division Polynomials of Mathematics – Class 10

Answer»

The correct choice is (d) 3

The EXPLANATION is: Since, one ZERO of the POLYNOMIAL is the additive inverse of the other.

Hence, the sum of roots will be zero.

The polynomial is x^2+(k-3)x-16=0

Sum of ZEROS or α+β=\(\frac {-coefficient \, of \, x}{coefficient \, of \, x^2} = \frac {k-3}{1}\)=0

k-3=0

k=3



Discussion

No Comment Found

Related InterviewSolutions