1.

What will be the value of k, so that the roots of the equation are x^2 + 2kx + 9 are imaginary?(a) -5 < k < 5(b) -3 < k < 3(c) 3 < k

Answer»

Correct choice is (b) -3 < k < 3

The best I can explain: Roots are imaginary. ∴ b^2 – 4ac < 0

(2K)^2 – 4(9)(1) < 0

4k^2 – 36 < 0

k^2 – 9 < 0

k^2 < 9

k < ±3

-3 < k < 3



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