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What work has to be performed in order to increase the velocity of a particle of rest mass `m_0` from `0.60c` to `0.80c`? Compare the result obtained with the value calculated from the classical formula. |
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Answer» The work done is equal to change in kinetic energy which is different in the two cases Classically i.e. in nonrelativistic mechanics, the change in kinetic energy is `1/2m_0c^2((0*8)^2-(0*6)^2)=1/2m_0c^20*28=1*14m_0c^2` Relativistically it is, `(m_0c^2)/(sqrt(1-(0*8)^2))-(m_0c^2)/(sqrt(1-(0*6)^2))=(m_0c^2)/(0*6)-(m_0c^2)/(0*8)=m_0c^2 (1*666-1*250)` `=0*416m_0c^2=0*42m_0c^2` |
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