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Which teem of the AP 3,15,27,39will be 132 more than its 54th term |
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Answer» First term of A.P. a = 3 and common difference d = 12a54 =\xa0a+(54-1)d = 3+53*12 = 3+636 = 639New term is 132 more than 639. So nth term = 132+639= 771771 = 3+(n-1)*12771= 3+12 n-12771 = 12n-912n= 771+9=780n= 780/12=65So 65 th term will be 132 more than its 54 th term. 65th |
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