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| 1. |
Which term of ap is 1 4 7 etc is 88 |
| Answer» The given AP is:1, 4, 7, ,...................88Here a=1\xa0and d=4-1=3Suppose there are nth terms=88{tex}\\mathrm{We}\\;\\mathrm{know}\\;\\mathrm{that}\\;{\\mathrm a}_{\\mathrm n}=\\mathrm a+(\\mathrm n-1)\\mathrm d{/tex}Now on substitution of value of a and d we get88 =1+(n-1)(3)88-1= 3n - 387 + 3 = 3n90 = 3nn = 30Hence, the 30th\xa0term of the given AP is 88. | |