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which term of tha AP :3,15,27....will be 132 more than its 54th term? |
| Answer» Here, first term = a = 3 and common difference = d = 15 – 3 = 12Let nth term of the given AP be 132 more than its 54th term, thenan = a54 + 132⇒ a + (n – 1)d = a + (54 – 1)d + 132⇒ (n – 1) d = (54 – 1)d + 132⇒(n – 1) 12 = (53)12 + 132⇒(n – 1) 12 = 768⇒(n – 1) = 64⇒ n = 65Hence, the 65th term will be 132 more than the 54th term. | |