Which term of the AP:3,8,13,18,....is78?

1.	Which term of the AP:3,8,13,18,....is78?
Answer» an=a+(n-1)d78=3+(n-1)578-3=(n-1)575/5=(n-1)15=n-115+1=n16=n The given A. P. is 3, 8, 13, 18, .....Here, a = 3 d = 8 - 3 = 5Let the nth term f=of the A. P. be 78Then, an = = a + (n - 1)d78 = 3 + (n - 1) 578 = 3 + 5n - 578= 5n - 25n = 78 + 2 = 80n = 80/5 = 16Hence, 16th term of the A .P. is 78. Hello,\xa0solution:\xa0as we know that nth term of an AP isTn\xa0= a+(n-1)dHere in given APa= 3d= 578 = 3+(n-1)578-3 = (n-1)575/5=n-115 = n-1n = 16\xa0Sixteenth term is 78.\xa0hHop it helps you\xa0

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