With light falling normally on a diffraction grating, the angle of diffraction of second order is equal to `45^(@)` for a wavelength `lambda_(1) = 0.65mum`. Find the angle of diffraction of third order for a wave length `lambda_(2) = 0.50 mu m`.

With light falling normally on a diffraction grating, the angle of dif

1.	With light falling normally on a diffraction grating, the angle of diffraction of second order is equal to `45^(@)` for a wavelength `lambda_(1) = 0.65mum`. Find the angle of diffraction of third order for a wave length `lambda_(2) = 0.50 mu m`.
Answer» From the fromula `d sin theta = m lambda` we have `d sin 45^(@) =2lambda_(1) = 2 xx 0.65 mu m` or `d = 2sqrt(2) xx 0.65mu m` Then for `lambda_(2) = 0.50` in the thrid order `2sqrt(2) xx 0.65 sin theta = 3 xx 0.50` `sin theta = (1.5)/(1.3 xx sqrt(2)) = 0.81602` This gives `theta = 54.68^(@) ~~55^(@)`

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With light falling normally on a diffraction grating, the angle of diffraction of second order is equal to `45^(@)` for a wavelength `lambda_(1) = 0.65mum`. Find the angle of diffraction of third order for a wave length `lambda_(2) = 0.50 mu m`.

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