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Without using trigonometric tables , evaluate the following : `(cot(90^(@)-theta)*sin(90^(@)-theta))/(sintheta)+(cot40^(@))/(tan50^(@))-(cos^(2)20+cos^(2)70^(@))` |
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Answer» `(cot(90^(@)-theta)*sin(90^(@)-theta))/(sintheta)+(cot40^(@))/(tan50^(@))-(cos^(2)20^(@)+cos^(2)70^(@))` `=(tan*costheta)/(sintheta)+(cot(90^(@)-50^(@)))/(tan50^(@))-{cos^(2)(90^(@)-70^(@))+cos^(2)70^(@)}` `=(sintheta*costheta)/(costheta*sintheta)+(tan50^(@))/(tan50^(@))-(sin^(2)70^(@)+cos^(2)70^(@))` `=1+1-1=1` |
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