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Without using trigonometric tables,prove that tan48°tan23°tan42°tan67°=1 |
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Answer» Are, dekho... tan(90-thita) = cot thita.... so agar tan 48 hai use tan(90-42) likha.... or use, cot 42° samjhe..... ab cot 42 × tan 42 = 1/tan42×tan42=1..... samjhe Puja ni smj aaya yar tan 48° tan 23° tan 42° tan 67° = tan (90° - 42°) tan (90° - 67°) tan 42° tan 67° = cot 42° cot 67° tan 42° tan 67° = (cot 42° tan 42°) (cot 67° tan 67°) = 1×1 = 1...............proved Tan48° Tan23° Tan(90-48) Tan(90-23).Tan48 Tan23 Cot48 Cot23. 1 |
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