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| 1. |
Write the HCF of 52 and 117 in the form of 52m +117n |
| Answer» Let us find HCF of 52 and 117 by Euclid\'s division algorithm.Since 117>52117 = 52 × 2 + 1352 = 13 × 4 + 0Therefore HCF (52, 117) = 13Now, 13 = 52×(-2) + 117×113 = 52x + 117y where X = -2 and y = 1 | |