InterviewSolution
Saved Bookmarks
| 1. |
Write the number of points of intersection of the curves 2y = - 1 and y = cosec x. |
|
Answer» Y = cosec x and y = - \(\frac{1}2\) So \(\frac{1}{sinx}\) = \(\frac{-1}2\) Sin x = -2 Which is not possible So There are 0 points of intersection. |
|