1.

Write the number of points of intersection of the curves 2y = - 1 and y = cosec x.

Answer»

Y = cosec x and y = - \(\frac{1}2\)

So

\(\frac{1}{sinx}\) = \(\frac{-1}2\)

Sin x = -2 

Which is not possible 

So 

There are 0 points of intersection.



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