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| 1. |
write the number of solution of the following pair of linear equationx+2y-8=0 , 2x+4y=16 |
| Answer» On comparing with standard equation, we get\xa0{tex}a_1 = 1, b_1 = 2, c_1 = -8\\\\a_2 = 2, b_2 = 4, c_2 = -16{/tex}The equations are consistent and dependent with infinitely many solutions, if and only if\xa0{tex}{a_1\\over a_2} = {b_1\\over b_2} = {c_1\\over c_2}{/tex}{tex}=>{1\\over 2} ={2\\over 4} = {-8\\over -16}\\\\=> {1\\over 2} ={1\\over 2} = {1\\over 2}{/tex}So the given pair of linear equations\xa0have many solutons. | |