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Write the quadratic polynomial having -1/4,1 as it\'s zeroes\xa0 |
| Answer» Ans. Let equation is ax2\xa0+ bx + c = 0, roots are\xa0{tex}-{1\\over 4},1{/tex}.We know that,Sum of roots =\xa0{tex}-{b\\over a}{/tex}=>\xa0{tex}-{1\\over 4} + 1 = -{b\\over a}{/tex}{tex}=> {3\\over 4} = -{b\\over a}{/tex}=> b = -3 and a = 4AlsoProduct of roots =\xa0{tex}c\\over a{/tex}=>\xa0{tex}-{1\\over 4}\\times 1 = {c\\over a}{/tex}{tex}=> -{1\\over 4}= {c\\over a}{/tex}c = -1 and a = 4Put Values of a,b,c in equation we get,4x2\xa0- 3x -1 = 0 Requried equation | |