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Write the value of the square root of i. |
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Answer» Let \(\sqrt{i}\) = \(\sqrt{a+ib}\) .........….1 Squaring both sides, we get i2 = (a2- b2) +2aib By comparing real and imaginary term, we get 2ab = 1 and a2- b2 = 0 By solving these we get a = b = \(\frac{1}{\sqrt{2}}\) By putting value of a and b in 1, we get \(\sqrt{i}\) = ± \(\frac{1}{\sqrt{2}}\) + \(\frac{1}{\sqrt{2}}\)i \(\sqrt{i}\) = ± \(\frac{1}{\sqrt{2}}\) (1+i) |
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