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| 1. |
(X+1)\\2 + (y-1)\\3= 8(X-1)/3 + (y+1)/2 =9Find the value of x and y |
| Answer» {tex}\\frac { x + 1 } { 2 } + \\frac { y - 1 } { 3 } = 9{/tex}\xa0or, 3(x + 1) + 2(y -1) = 54or, 3x + 3 + 2 y - 2 = 54or, 3x + 2y +1 = 54or, 3x + 2y = 53..........(i)and\xa0{tex}\\frac { x - 1 } { 3 } + \\frac { y + 1 } { 2 } = 8{/tex}\xa0or, 2(x -1 ) + 3 (y + 1) = 48or, 2x - 2 + 3y + 3 = 48or, 2x + 3y +1 = 48or, 2x +3y = 47........(ii)Multiply eqn.(i) by 3, multiply eqn.(ii) by 2 and subtracting both eqn{tex}\\therefore {/tex}\xa0{tex}x = \\frac { 65 } { 5 } = 13{/tex}\xa0Substitute the value of x in eqn. (ii),2(13) + 3y = 47or, 26 + 3y = 473y = 47-26 = 21{tex}\\therefore {/tex}\xa0{tex}y = \\frac { 21 } { 3 } = 7{/tex}\xa0Hence x = 13, y = 7. | |