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| 1. |
(x-1) (2x-1) find discrimination |
| Answer» (x - 1)(2x - 1) = 0{tex}\\Rightarrow{/tex} 2x2 - x - 2x + 1 = 0{tex}\\Rightarrow{/tex} 2x2 - 3x + 1 = 0Here, a = 2, b = -3, c = 1D = b2 - 4ac{tex}= ( - 3 ) ^ { 2 } - 4 \\times 2 \\times 1{/tex}= 9 - 8 = 1\xa0 | |