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X-1=8(y-1),x=y^2 solve for value of x and y |
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Answer» Then x=y^2X=(1)^2X=1 X_1=8y_8 (1) ,x=y^2Put the value of x^2 in eq (1)Y^2_1=8y_8 Y^2_8y+7=0Y^2_7y_y+7=0Y (y_7) _1 (y_7)=0(Y_7) (y_1)=0Y=7 ,y=1 x - 1 = 8(y - 1)y^2 - 1 = 8y - 8 (∵x=y^2)y^2 - 8y -1 +8 = 0y^2 - 8y +7 = 0y^2 - y -7y + 7 = 0y (y-1) -7(y-1) = 0(y -7) (y-1) = 0∴ either (y-7) =0 OR (y-1) = 0∴ y = 7 OR y= 1i) If y= 7 , then x = y^2 = (7)^2 = 49ii) If y = 1, then x = y^2 = (1)^2 = 1 |
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