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X^2+1 factor of x^4+x^3+8x^+ax+b find value of a and b |
| Answer» x^2+x+7 ____________________x^2+1√x^4+x^3+8x^2+ax+b x^4+ 0 + x^2 - - - _____________________ x^3+7x^2+ax+b x^3+ 0 + x - - - ______________________ 7x^2 + ax-x+b 7x^2 + 7 - - _______________________ ax - x + b -7 _______________________Now, we take common from the remainder.Since, x^2+ 1 is a factor.Therefore, Remainder= 0x( a-1) + b -7= 0i.e. a-1=0 ; b-7=0 a= 1 ; b= 7 | |