InterviewSolution
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InterviewSolution
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X^2-3√5x+10 = 0 |
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Answer» x²-3√5x+10=0Splitting the middle term, we\xa0get=> x²-2√5x-√5x+10=0=> x²-2√5x-√5x+2×5=0=> x²-2√5x+√5x +2×√5×√5=0=> x(x-2√5)-√5(x-2√5)=0=> (x-2√5)(x-√5)=0=> x-2√5 =0 Or x-√5 = 0=> x = 2√5 Or x = √5Therefore,Roots of given Quadratic equation are:2√5 Or √5\xa0 x²-3√5x+10=0.........Splitting the middle term, weget......=> x²-2√5x-√5x+10=0........=> x²-2√5x-√5x+2×5=0.........=> x²-2√5x+√5x +2×√5×√5=0........=> x(x-2√5)-√5(x-2√5)=0........=> (x-2√5)(x-√5)=0........=> x-2√5 =0 Or x-√5 = 0.......=> x = 2√5 Or x = √5........Therefore,........Roots of given Quadratic equation are.......:2√5 Or √5......••••• |
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