InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
X^2-5x=14 find value of x ? |
|
Answer» X²-5X=14 X²-5X-14=0X²-7X+2X-14=0X(X-7)+2(X-7)=0(X-7)(X+2)=0(X-7)=0 (X+2)=0X=7 and X=-2 it is done by this this x2-5x-14=0 x2+2x-7x-14=0. x(x+2)-7(x+2)=0 (x+2) (x-7) =0 if x+2=0. x=-2 Not Valid x-7=0 x=7 7,-2 x*2-5x-14=0=x*2-7x -2x-14=0=x(x-7)-2(x-7)=0 =(x-7)(x-2)so x=7,2 |
|