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`|(x^(2)-x+1, x-1),(x+1,x+1)|` |
Answer» Correct Answer - `x^(3)-x^(2) + 2` `Delta =(x^(2)-x+1)(x-1)-(x+1)(x-1) = (x^(3)+1)-(x^(2)-1) = (x^(3)-x^(2)+2)` |
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