X 2y_+_ =-1and x-y _ =3 solve it by elimination method 2 3 3

1.	X 2y_+_ =-1and x-y _ =3 solve it by elimination method 2 3 3
Answer» {tex}\\frac{x}{2} + \\frac{{2y}}{3} = - 1{/tex} ....(1){tex}x - \\frac{y}{3} = 3{/tex} ...(2)\tElimination method: Multiplying equation (2) by 2, we get (3)\t{tex}2x - \\frac{2}{3}y = 6{/tex} ....(3)\t{tex}\\frac{x}{2} + \\frac{{2y}}{3} = - 1{/tex} ....(1)\tAdding (3) and (1), we get\t{tex}\\frac{5}{2}x = 5{/tex}\t\xa0⇒ x =2\tPutting value of x in (2), we get\t2− {tex}\\frac{y}{3}{/tex}= 3\t⇒ y =−3\tTherefore, x =2 and y =−3\tSubstitution method:{tex}\\frac{x}{2} + \\frac{{2y}}{3} = - 1{/tex} ....(1)\t{tex}x - \\frac{y}{3} = 3{/tex} ....(2)\tFrom equation (2), we can say that {tex}x = 3 + \\frac{y}{3} = \\frac{{9 + y}}{3}{/tex}\tPutting this in equation (1), we get\t{tex}\\frac{{9 + y}}{6} + \\frac{2}{3}y = - 1{/tex}\t{tex} \\Rightarrow \\;\\frac{{9 + y + 4y}}{6} = - 1{/tex}\t⇒ 5y +9=−6\t⇒ 5y =−15\t⇒ y =−3\tPutting value of y in (1), we get\t{tex}\\frac{x}{2} + \\frac{2}{3}( - 3) = - 1{/tex}\t⇒ x = 2\tTherefore, x =2 and y =−3.

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