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(X+3) is a factor of x³+ax²-bx+6 & a+b=7.Find the value of a&b. |
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Answer» a=0 and b=7 First divide the given polynomial by (x+3) then you will get the remainder 6-(27-9a-3b) which you know is equal to 0 as it is given that (x-3) is a factor of the given polynomial. Then form an equation 6-(27-9a-3b)=0 which after solving you will get 3a+b=7. Then you will have two equations 3a+b=7 and a+b=7. Solve them you\'ll get ans |
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