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X =3 is one root of quadratic x² -2kn-6=0 find the value of k

Answer» x2-2kn-6=0(3)2-2k(3)-6=09-6k-6=03-6k=0-6k=3K=-3/6=-1/2
x2 - 2kx - 6 = 0(3)2 - 2k(3) - 6 = 09 - 6k - 6 = 0-6k - 3 = 0- 6k = 3k = 3/-6k = -1/2
Put x=3 and solve


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