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| 1. |
X=3, x^2-2kx-6=0 find the value of k |
| Answer» Given it\'s one root of the equation x² - 2kx - 6 = 0one of its root x = 3\xa0for finding the value of k put the value of x in this equation.(3)² - 2k(3) - 6 = 09 - 6k - 6 = 06k = 3k = 3/6k = 1/2hence,the value of k = 1/2x² - 2(1/2)x - 6 = 0x² - x - 6 = 0x² - 3x + 2x - 6 = 0x(x - 3) + 2(x - 3) = 0(x + 2)(x - 3) = 0x = 3 , x = -2 | |