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X isto power 2-4ax+4a isto power 2-b isto power 2 by completing square method

Answer» We have the following equation,{tex}x^2-4ax-b^2+4a^2=0{/tex}{tex}\\Rightarrow{/tex}\xa0x2\xa0- 4ax + (4a2\xa0- b2) = 0Factorise the equation{tex}\\Rightarrow{/tex}\xa0x2\xa0- 4ax + (2a + b)(2a - b) = 0{tex}\\Rightarrow{/tex}\xa0x2\xa0- (2a + b)x - (2a - b)x + (2a + b)(2a - b) = 0{tex}\\Rightarrow{/tex}\xa0x[ x - (2a + b)] - (2a - b)[x -\xa0( 2a + b) ] = 0{tex}\\Rightarrow{/tex}\xa0[x - (2a + b)] [x - (2a - b)] = 0{tex}\\Rightarrow{/tex}\xa0x -\xa0(2a + b) = 0 or\xa0x -\xa0(2a -\xa0b) = 0{tex}{/tex}Therefore, x = 2a + b or x = 2a - b are solutions of the equation.


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