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| 1. |
(x÷x+1)2. -. 5(x÷x+1). +. 6 = 0 |
| Answer» Ans.\xa0\\(({x \\over (x+1)})^2 - 5 ({x \\over (x+1)}) + 6 = 0\\)\\(Put \\space ({x \\over (x+1)}) = y, We \\space get \\)=>\xa0\\(y^2 -5y +6 =0\\)=>\xa0\\(y^2 - 3y -2y +6 = 0\\)=>\xa0\\(y(y-3) -2(y-3) = 0\\)=>\xa0\\((y-3)(y-2) = 0\\)=> y = 3 , 2Now,\xa0\\({x\\over (x+1) } = 3 \\space \\space or \\space \\space {x\\over (x+1) } = 2\\)=> x = 3x +3 or x = 2x + 2=> x = -3/2 or x = -2\xa0Values of x = -3/2, -2\xa0 | |