1.

X + ✅y =7 and ✔x + y = 11

Answer» Given equations are{tex}\\frac{x}{4}{/tex}\xa0+\xa0{tex}\\frac{2y}{3} = 7{/tex}...............(i)and\xa0{tex}\\frac{x}{6}{/tex}\xa0+\xa0{tex}\\frac{3y}{5} = 11{/tex} .................(ii)From equation (i), we get{tex}\\frac{x}{4}{/tex}\xa0+\xa0{tex}\\frac{2y}{3} = 7{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{x}{4}{/tex}\xa0= 7 -\xa0{tex}\\frac{2y}{3}{/tex}{tex}\\Rightarrow{/tex}\xa0{tex} x = 4(7 -\\frac{2y}{3}){/tex}{tex}\\Rightarrow{/tex}\xa0x = 28 -\xa0{tex}\\frac{8y}{3}{/tex}.................(iii)substituting x = 28 -\xa0{tex}\\frac{8y}{3}{/tex}\xa0in equation (ii), we get{tex}\\frac { 28 - \\frac { 8 y } { 3 } } { 6 } + \\frac { 3 y } { 5 } = 11{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}\\frac { 84 - 8 y } { 18 } + \\frac { 3 y } { 5 } = 11{/tex}{tex}\\Rightarrow{/tex}{tex}\\frac{420 - 40y + 54y}{18 \\times 5}{/tex}\xa0= 11{tex}\\Rightarrow{/tex}\xa0420 + 14y = 990{tex}\\Rightarrow{/tex} 14y = 570{tex}\\Rightarrow{/tex} y =\xa0{tex}\\frac{570}{14}{/tex}\xa0=\xa0{tex}\\frac{285}{7}{/tex}When y =\xa0{tex}\\frac{285}{7}{/tex}, equation (iii) becomes{tex}x = 28 - \\frac { 8 \\times \\frac { 285 } { 7 } } { 3 }{/tex}{tex}\\Rightarrow{/tex}\xa0{tex} x = 28 -\\frac{8 \\times 285}{21}{/tex}{tex}\\Rightarrow{/tex}{tex}x = \\frac{588 - 2280}{21}{/tex}\xa0=\xa0{tex}\\frac{-1692}{21}{/tex}{tex}\\Rightarrow{/tex} -{tex}x =\\frac{564}{7}{/tex}{tex}\\therefore{/tex}\xa0x = -{tex}\\frac{564}{7}{/tex}, y =\xa0{tex}\\frac{285}{7}{/tex} is the solution of given system of equations.
Sorry nahi samajh me aya . Pic


Discussion

No Comment Found

Related InterviewSolutions