x-y+z=4,x-2y-2z=9,2x+y+3z=1

1.	x-y+z=4,x-2y-2z=9,2x+y+3z=1
Answer» x-y+z=4 ...(1) x-2y-2z= 9 ...(2) 2x+y+3z= 1...(3)Multiply eq(1) by 2, we get 2x-2y+2z =4.....(4)Add eq(4) and eq(2), we get, 2x-2y+2z= 8 x-2y-2z=9 ----------------------- 3x-4y= 17 ...(5)Multiply eq(2) by 3 ,we get 3x-6y-6z= 27 ....(6)Multiply eq(3) by 2, we get 4x+2y+6z= 2 ...(7)Adding eq(6) and\xa0eq(7), we get3x-6y-6z= 274x+2y+6z=2-----------------7x-4y=29 ...(8)Subtracting eq(5) from eq(8), we get7x-4y=293x-4y=17--------------------4x=12x=12/4= 3\xa0Substituting the value of x in eq(8), we get7x3- 4y= 2921--4y=29-4y= 29-21-4y=8y=-8/4=-2Substituting the value of x and y in eq (1), we get3-(-2)+z = 4\xa03+2+z=45+z=4z=4-5z=-1So, x= 3, y=-2 and z= -1\xa0\xa0\xa0

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