1.

\xa0Write the zeroes of the polynomial 4x2\xa0–4 x +1.

Answer» 4x2 - 4x + 1= (2x)2 - 2 . 2x . 1 + (1)2= (2x - 1)2 [Using identity a2 - 2ab + b2]= (2x - 1)(2x - 1)Taking, 2x - 1 = 0 and 2x - 1 = 0x = 1/2 and x = 1/2Therefore, the zeroes of given polynomial are 1/2 and 1/2


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