InterviewSolution
Saved Bookmarks
| 1. |
Xki power 2 - 2ax-(4b ki pwer 2 - a ki power 2 ) =0Solve the following quadratic equation for X |
| Answer» {tex}x^2\xa0- 2ax - (4b^2\xa0- a^2) = 0{/tex}{tex} \\Rightarrow{/tex}\xa0{tex}x^2\xa0- 2ax + (a^2\xa0- 4b^2) = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x^2\xa0- 2ax + (a - 2b)(a + 2b) = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x^2\xa0- (a - 2b)x - ( a+ 2b)x + (a - 2b) (a + 2b) = 0{/tex}{tex}[2ax=(a-2b)x+(a+2b)x]{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x[x- (a - 2b )] - (a + 2b) [x - (a - 2b)] = 0{/tex}{tex}\\Rightarrow{/tex}\xa0[x - (a - 2b)] [x - (a + 2b)] = 0{tex}\\Rightarrow{/tex}\xa0x - (a - 2b) = 0 or x - (a + 2b) = 0{tex}\\Rightarrow{/tex}\xa0x = a -2b or x = a + 2b | |