

InterviewSolution
Saved Bookmarks
1. |
`y=sqrt(sin +cos x+sqrt(sinx+ cos x +sqrt(sin x +cos x +....oo))) " then find " dy/dx` |
Answer» `y=sqrt(sin +cos x+sqrt(sinx+ cos x +sqrt(sin x +cos x +....oo))) ` `rArr sqrt(sin x +cos x+y )` `rArr y^2 =sin x+ cos x+y ` `y^2-y =sin x+cos x` Differentiate both sides w.r.t. x, `2y(dy)/(dx))-dy/dx = cos x -sin x ` `rArr dy /dx (2y -1) =cos x -sin x ` `rArr dy /dx =(cos x-sin x )/(2y -1)` |
|