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`y=sqrt(sin +cos x+sqrt(sinx+ cos x +sqrt(sin x +cos x +....oo))) " then find " dy/dx`

Answer» `y=sqrt(sin +cos x+sqrt(sinx+ cos x +sqrt(sin x +cos x +....oo))) `
`rArr sqrt(sin x +cos x+y )`
`rArr y^2 =sin x+ cos x+y `
`y^2-y =sin x+cos x` Differentiate both sides w.r.t. x,
`2y(dy)/(dx))-dy/dx = cos x -sin x `
`rArr dy /dx (2y -1) =cos x -sin x `
`rArr dy /dx =(cos x-sin x )/(2y -1)`


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