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`y=tan^-1[(3x-x^3)/(1-3x^2)],-1/sqrt3ltxlt1/sqrt3` |
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Answer» `y = tan ^(-1)((3x-x^(3))/(1-3x^(2)))` Let `x + tantheta` `rArr theta= tan^(-1) x` `rArr y = tan^(-1)((3tan theta- tan^(3)theta)/(1-3 tan^(2)theta))` `= tan^(-1) (tan3theta) = 3theta = 3 tan^(-1)x ` `rArr (dy)/(dx) = 2 (d)/(dx) tan^(-1)x = (3)/(1+x^(2))` |
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