1.

यदि `1.5x=0.04y` है तो `(y^(2)-x^(2))/(y^(2)+2xy+x^(2))` का मान क्या होगा?A. `730/77`B. `73/77`C. `73/7701`D. `74/77`

Answer» Correct Answer - B
`1.5x=0.04y`
`implies x/y=0.04/1.5=4/100xx10/15=2/75`
`:. (y^(2)-x^(2))/(y^(2)+x^(2)+2xy)=((y-x)(y+x))/((y+x)^(2))`
`implies (y-x)/(y+x)=(75-2)/(75+2)73/77`


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