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यदि `1.5x=0.04y` है तो `(y^(2)-x^(2))/(y^(2)+2xy+x^(2))` का मान क्या होगा?A. `730/77`B. `73/77`C. `73/7701`D. `74/77` |
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Answer» Correct Answer - B `1.5x=0.04y` `implies x/y=0.04/1.5=4/100xx10/15=2/75` `:. (y^(2)-x^(2))/(y^(2)+x^(2)+2xy)=((y-x)(y+x))/((y+x)^(2))` `implies (y-x)/(y+x)=(75-2)/(75+2)73/77` |
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