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यदि `(2a-1)^(2)+(4b-3)^(2)+(4c+5)^(2)=0` तो `(a^(3)+b^(3)+c^(3)-3abc)/(a^(2)+b^(2)+c^(2))` का मान क्या होगा?A. `3 3/8`B. `2 3/8`C. 0D. `1 3/8` |
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Answer» Correct Answer - C `(2a-1)^(2)+(4b-3)^(2)+(4c+5)^(2)=0` to find `implies (a^(3)+b^(3)+c^(3)-3abc)/(a^(2)+b^(2)+c^(2))` `implies (1/2(a+b+c)[(a-b)^(2)+(b-c)^(2)+(c-a)^(2)])/(a^(2)+b^(2)+c^(2))` `implies` then `2a-1=0` `a=1//2` `implies 4b-3=0` `implies b=3/4` `implies 4c+5=0` `implies c=(-5)/4` `=a+b+c=1/2+3/4-5/4=0` `implies (1/2(a+b+c)[(a-b)^(2)+(b-c)^(2)+(c-a)^(2)])/(a^(2)+b^(2)+c^(2))` `=(1/2(0)[(a-b)^(2)+(b-c)^(2)+(c-a)^(2)])/(a^(2)+b^(2)+c^(2))=0` |
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