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यदि `2x-1/(2x)=5,x!=0` हों तो `x^(2)+1/(16x^(2))-2` का मान ज्ञात कीजिये?A. `19/4`B. `23/4`C. `27/4`D. `31/4` |
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Answer» Correct Answer - A `2x-1/(2x)=5` divide by 2 both side `x-1/(4x)=5/2` Squaring both side `x^(2)+1/(16x^(2))-2xx x xx 1/(4x)=25/4` `x^(2)+1/(16x^(2))-1/2=25/4` ltbgt `x^(2)+1/(16x^(2))=25/4+1/2=27/4` So, `x^(2)+1/(16x^(2))-2=27/4-2` `x^(2)+1/(16x^(2))-2=19/4` |
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