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यदि `(3a+1)^(2)+(b-1)^(2)+(2c-3)^(2)=0`, है तो `(3a+b+2c)` का मान क्या होगा?A. 3B. `-1`C. `2`D. `5` |
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Answer» Correct Answer - A `(3a+1)^(2)+(b-1)^(2)+(2c-3)^(2)=0` `=(3a+1)^(2)=0` `implies 3a=-1implies a=(-1)/3` `(b-1)^(2)=0impliesb-1=0` `implies b=1` `(2c-3)=0impliesc=3/2` `:. 3a+b+2c=3xx(-1)/3+1+3/2xx2` `=-1+1+3=3` |
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