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यदि `a+b+c=0` है तो `(a^(2)+b^(2)+c^(2))/(a^(2)-bc)` का मान क्या होगा? |
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Answer» Correct Answer - C `a+b+c=0` Assume values `a=2, b=-2, c=0` `a+b+c=2-2+0=0` (satisfy) `:. (a^(2)+b^(2)+ c^(2))/(a^(2)-bc)` `implies (4+4+0)/(4-0)implies8/4=2` Alternate `a+b+c=0` `b+c=-a` Squaring both sides `(b+c)^(2)=a^(2)` `b^(2)+c^(2)+2bc=a^(2)` `b^(2)+c^(2)=a^(2)-2bc` `:. (a^(2)+b^(2)+c^(2))/(a^(2)-bc)` `implies (a^(2)+a^(2)-2bc)/(a^(2)-bc)` `= (2a^(2)-2bc)/(a^(2)-bc)implies(2(a^(2)-bc))/(a^(2)-bc)=2` |
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