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यदि `ax+by=1` और `bx+ay=(2ab)/(a^(2)+b^(2))` हो तो `(x^(2)+y^(2))(a^(2)+b^(2))` किसके बराबर है?A. 1B. 2C. 0.5D. 0 |
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Answer» Correct Answer - A `ax+by=1` `bx+ay=(2ab)/(a^(2)+b^(2))` Let `a=b=1` then `x+y=1` …………i `x+y=(2xx1xx1)/(1+1)=1`………..ii Now put `x=y=1/2` in eq i and ii `1/2+1/2=1` and equation ii `1/2+1/2=1` Value of `(x^(2)+y^(2))(a^(2)+b^(2))` `=(1/2)^(2)+(1/2)^(2)(1+1)` `=(1/4+1/4)xx2=2/4xx2=1` |
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