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यदि `p=99` तो `p(p^(2)+3p+3)` का मान क्या होगा?A. 999999B. 1000000C. 1000001D. 999998 |
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Answer» Correct Answer - A `P(p^(2)+3p+3)` `=p^(3)+3p^(2)+3p+1-1` (on adding and subtraction one both side) `=(p+1)^(2)-1` `(99+1)^(3)-1=100^(3)-1` `=1000000-1=999999` |
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