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यदि `P=999` तो `P(P^(2)+3P+3)` का मान बताइए?A. 9999B. 999999C. 99999D. 999999 |
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Answer» Correct Answer - B `P=99` `P(P^(2)+3P+3)` `=P^(3)+3P^(2)+3P+1-1` `=(P+1)^(3)-1=(99+1)^(3)-1` `=(100)^(3)-1=(100)^(3)-1` `=1000000-1=999999` |
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