1.

यदि `P=999` तो `P(P^(2)+3P+3)` का मान बताइए?A. 9999B. 999999C. 99999D. 999999

Answer» Correct Answer - B
`P=99`
`P(P^(2)+3P+3)`
`=P^(3)+3P^(2)+3P+1-1`
`=(P+1)^(3)-1=(99+1)^(3)-1`
`=(100)^(3)-1=(100)^(3)-1`
`=1000000-1=999999`


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