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यदि `root(3)(a)+root(3)(b)=root(3)(c)` है तो `(a+b-c)^(3)+27abc` का साधारणीकृत मान क्या होगा?A. -1B. 3C. -3D. 0 |
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Answer» Correct Answer - D `root(3)(a)+root(3)(b)=root(3)(c)` Take cube both sides `(root(3)(a)+root(3)(b))^(3)=(root(3)(c))^(3)` `implies a+b+3a^(1/3)b^(1/3) (root(3)(a)+root(3)(b))=c` `implies a+b+3a^(1/3)b^(1/3)c^(1/3)=c` `implies a+b-c=-3a^(1/3)b^(1/3)c^(1/3)` Again take cube both sides `implies (a+b-c)^(3)=-27abc` `implies(a+b-c)^(3)+27abc=0` Alternate: Put value of `a=0` `b=1, c=1` value of `(a+b-c)^(3)+27abc` `=(0+1-1)^(3)+27x0xx1xx1=0` |
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