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यदि Sn = 4 (3n – 1) हो, तो Tn + 1 ज्ञात करो । |
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Answer» हम जानते है कि Tn + 1 = Sn + 1 – Sn Tn + 1 = 4 (3n + 1 – 1) – 4 (3n – 1) = 4 (3n + 1 – 1 – 3n + 1) = 4 (3n + 1 – 3n) = 4 (3n) (3 – 1) = 4 (3n) (2) ∴ Tn + 1 = 8 (3n) |
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