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यदि व्यंजक `(x^(2))/(y^(2))+tx+(y^(2))/4` एक पूर्ण वगै है तो `t` का मान होगा?A. `+-1`B. `+-2`C. `0`D. `+-3`

Answer» Correct Answer - A
`(x^(2))/(y^(2))+tx+(y^(2))/4` (given)
To make it a perfect square it should be in the form.
`A^(2) +-2AB+B^(2)=(A+-B)^(2)` ltbr `=(x/y)^(2)+-tx+(y/2)^(2)`
`= A^(2) +-2AB+B^(2)`
`A=x/y,B=y/2` & `2AB=tx`
So `tx=+-2xx x/y xx y/2`
`tx=+-x`
`t=+-1`


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