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यदि `x+1=sqrt(y)+3,ygt0`, तो `1/2 xx((x^(3)-6x^(2)+12x-8)/(sqrt(y))-y)` का मान क्या होगा?A. `1/2`B. `-1`C. `1`D. `0` |
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Answer» Correct Answer - D According to the question `x+1=sqrt(y)+3,ygt0` `implies 1/2((x^(3)-6x^(2)+12x-8)/(sqrt(y))-y)=?` Put `x=4` & `y=4` Now `implies 1/2((x^(3)-6x^(2)+12x-8)/(sqrt(y))-y)` `=1/2((x-2)(3))/(sqrt(y))-y)` `=1/2(((4-2)^(3))/(sqrt(4))-4)` `=1/2(8/2-4)=1/2(4-4)=0` |
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