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यदि `x^(2)+y^(2)+2x+1=0` है तो `x^(31)+y^(35)` का मान क्या होगा?A. -1B. 0C. 1D. 2 |
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Answer» Correct Answer - A `x^(2)+y^(2)+2x+1=0` `implies x^(2)+2x+1+y^(2)=0` `(x+1)^(2)+y^(2)=0` Hence both terms are squares and there addition is zero so, it can be possible only when both terms are zeros. `:. x+1=0` `impliesx=-1` `y=0` `:. x^(31)+y^(35)` =`(-1)^(31)+(0)^(35)=-1` |
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