1.

यदि `x^(2)+y^(2)+2x+1=0` हो तो `x^(31)+y^(35)` का मान निकालें।A. -1B. 1C. 0D. 2

Answer» Correct Answer - A
`x^(2)+y^(2)+2x+1=0`
`(x+1)^(2)+y^(2)=0`
Let `(x+1)^(2)=0, y^(2)=0`
`x=-1,y=0`
Now `x^(31)+y^(35)=(-1)^(31)+(0)^(35)`
`=-1`


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