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यदि `x^(2)+y^(2)+z^(2)=2(x+z-1)` है तो `x^(3)y^(3)+z^(3)=?`A. -1B. 2C. 0D. 1 |
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Answer» Correct Answer - B Given `x^(2)+y^(2)+z^(2)=2(x+z-1)` Find `x^(3)+y^(3)+z^(3)=?` `implies x^(2)+y^(2)+z^(2)=2(x+z-1)` `implies x^(2)+y^(2)+z^(2)=2x+2z-2` `implies x^(2)+y^(2)+z^(2)=2x+2z-1-1` `implies (x^(2)+1-2x)+y^(2)+(z^(2)+1-2z)=0` `implies (x-1)^(2)+y^(2)+(z-1)^(2)=0` `implies (x-1)^(2)=0` `implies x=1` `implies y^(2)=0` `implies y=0` `implies (z-1)^(2)=0` `implies z=1` Value substituted in question, `implies x^(3)+y^(3)+z^(3)` `implies 1^(3)+0+1^(3)` `implies 2` |
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