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यदि `x^(2)=y+z,y^(2)=z+x,z^(2)=x+y` है तो `1/(x+1)+1/(y+1)+1/(z+1)` का मान क्या होगा?A. -1B. 1C. 2D. 41 |
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Answer» Correct Answer - B `x^(2)=y+z` `y^(2)=z+x` `z^(2)=x+y` `implies x^(2)+x=x+y+z` Adding `x` on both sides `x(x+1)=x+y+z` `1/((x+1))=x/(x+y+z)` Similarly `1/(y+1)=y/(x+y+z)` and `1/(z+1)` `=z/(x+y+z)` `:. 1/(x+1)+1/(y+1)+1/(1+z)` `=x/(x+y+z)+y/(x+y+z)+z/(x+y+z)` `=(x+y+z)/(x+y+z)=1` |
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